最全面的地图JavaScript离线版开发

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2024年7月24日发(作者：)

public static double[] wgs2bd(double lat, double lon){

double[] wgs2gcj = wgs2gcj(lat, lon);

double[] gcj2bd = gcj2bd(wgs2gcj[0], wgs2gcj[1]);

return gcj2bd;

}

/**

* GCJ坐标转百度坐标

* @param lat

* @param lon

* @return

*/

public static double[] gcj2bd(double lat, double lon) {

double x = lon, y = lat;

double z = (x * x + y * y) + 0.00002 * (y * x_pi);

double theta = 2(y, x) + 0.000003 * (x * x_pi);

double bd_lon = z * (theta) + 0.0065;

double bd_lat = z * (theta) + 0.006;

return new double[] { bd_lat, bd_lon };

}

public static double[] bd2gcj(double lat, double lon) {

double x = lon - 0.0065, y = lat - 0.006;

double z = (x * x + y * y) - 0.00002 * (y * x_pi);

double theta = 2(y, x) - 0.000003 * (x * x_pi);

double gg_lon = z * (theta);

double gg_lat = z * (theta);

return new double[] { gg_lat, gg_lon };

}

/**

* WGS坐标转GCJ坐标

* @param lat

* @param lon

* @return

*/

public static double[] wgs2gcj(double lat, double lon) {

double dLat = transformLat(lon - 105.0, lat - 35.0);

double dLon = transformLon(lon - 105.0, lat - 35.0);

double radLat = lat / 180.0 * pi;

double magic = (radLat);

magic = 1 - ee * magic * magic;

double sqrtMagic = (magic);

dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);

dLon = (dLon * 180.0) / (a / sqrtMagic * (radLat) * pi);

double mgLat = lat + dLat;

double mgLon = lon + dLon;

double[] loc = { mgLat, mgLon };

return loc;

}

private static double transformLat(double lat, double lon) {

double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * ((lat));

ret += (20.0 * (6.0 * lat * pi) + 20.0 * (2.0 * lat * pi)) * 2.0 / 3.0;

ret += (20.0 * (lon * pi) + 40.0 * (lon / 3.0 * pi)) * 2.0 / 3.0;

ret += (160.0 * (lon / 12.0 * pi) + 320 * (lon * pi/ 30.0)) * 2.0 / 3.0;

return ret;

}

private static double transformLon(double lat, double lon) {

double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * ((lat));

ret += (20.0 * (6.0 * lat * pi) + 20.0 * (2.0 * lat * pi)) * 2.0 / 3.0;

ret += (20.0 * (lat * pi) + 40.0 * (lat / 3.0 * pi)) * 2.0 / 3.0;

ret += (150.0 * (lat / 12.0 * pi) + 300.0 * (lat / 30.0 * pi)) * 2.0 / 3.0;

return ret;

}

/**

* 度分转度

* @param lat 纬度

* @param lon 经度

* @return

*/

public static double[] dufen2du(String lat, String lon){

double latD=ouble(ing(0, 2));

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