(本人菜鸟刚学)看网上教程写了一个很简单的HttpGet测试一下,结果出了一堆的报错! 代码: public static String getApi(String url){ String cont = null; HttpGet httpGet = new HttpGet(url); DefaultHttpClient httpClient = new DefaultHttpClient();
(本人菜鸟刚学)看网上教程写了一个很简单的 HttpGet测试一下,结果出了一堆的报错!
代码:
public static String getApi(String url){
String cont = null;
HttpGet httpGet = new HttpGet(url);
DefaultHttpClient httpClient = new DefaultHttpClient();
try {
HttpResponse httpResponse = httpClient.execute(httpGet);
int reCode = httpResponse.getStatusLine().getStatusCode();
if (reCode == HttpStatus.SC_OK) {
cont = EntityUtils.toString(httpResponse.getEntity());
return cont;
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return "";
}
报线程问题,看网上资料说从2.3以后就必须在线程里面运行,然后网上各种写法,看到头大坑爹的而且写进来还不行,接着报错...然后...擦还是不行....还是自己写一下.....希望可以帮助到新手
在onCreate里面先初始化
handler=new Handler(); //当然最上面还要定义private Handler handler;
然后在你的触发事件里面写
public void login_submit(View v){
new Thread(){
@Override
public void run() {
String url = "http://192.168.1.188/123.html";
rs = HttpApi.getApi(url);
handler.post(new Runnable() {
@Override
public void run() {
Toast.makeText(login.this,rs,Toast.LENGTH_SHORT).show();
}
});
}}.start();
}
好这样就差不多了。最后还要在
AndroidManifest.xml 里面加入一句 允许联网的权限
OK搞定。。。。
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