问题描述
限时送ChatGPT账号..我有一个 ANT 脚本,它有一个属性,其值可以是一行或多行,例如属性
I have an ANT script which will have a property whose value could be one or more lines e.g. property
prop1=
A_12.1_REL_B121000_10_18_2011.1700
A_12.1_REL_B121001_10_25_2011.6059
A_12.1_REL_B121001_10_25_2011.2201
A_12.1_REL_B121001_10_25_2011.2014
请注意,所有这些行都以 CRLF 结尾,文件结尾也是另一个 CRLF.现在我需要做的就是使用正则表达式选择最后一行.行数可以更少或更多,例如
Please see that all these lines end with a CRLF and end of file is also another CRLF. Now what I need to do is just select the last line using a regex. The number of lines could be less or more e.g
prop1=
A_12.1_REL_B121000_10_18_2011.1700
在第二种情况下,我需要选择这一行.我搜索了较旧的帖子,但找不到任何具体内容.有什么指点吗?
In the second case I need to select this single line . I have searched older posts, but could not find anything specific. Any pointers ?
推荐答案
如果您正在使用 ant-contrib>:
<loadfile srcFile="input.prop" property="test"/>
<propertyregex property="result"
input="${test}"
regexp="(.*$)"
select="\1"
/>
<echo message="Result is : ${result}"/>
这将始终打印输入属性文件的最后一行:
This will always print the last line of your input properties file :
[echo] Result is : A_12.1_REL_B121001_10_25_2011.2014
这篇关于正则表达式选择多行字符串中的最后一行的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
更多推荐
[db:关键词]
发布评论