JAVA计算两条直线的交点(判断两条线段相交)

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JAVA计算两条直线的交点(判断两条线段相交)

//计算两条直线的交点
//输入四个点,前两个点确定线段1,后两个点确定线段2
//输出交点坐标
public class Main{public static void main(String args[]){double[] point1= new double[]{10.0,29.0};double[] point2 = new double[]{1.0,3.0};double[] point3 = new double[]{40,2};double[] point4 = new double[]{90,3};double[] node = cross(point1,point2,point3,point4);if(node==null)System.out.println(false);else System.out.println(node[0]+","+node[1]);HashSet<String> set = new HashSet<>();set.add(node[0]+":"+node[1]);for(String item:set){System.out.println(item);}}public static double[] cross(double[] point1,double[] point2,double[] point3,double[] point4){if((point2[1]-point1[1])*(point4[0]-point3[0])==(point4[1]-point3[1])*(point2[0]-point1[0]))return null;if(point2[0]-point1[0]==0){double k2 = (point4[1]-point3[1])/(point4[0]-point3[0]);double b2 = point3[1]-point3[0]*k2;double cross_x = point1[0];double cross_y = k2*cross_x+b2;return new double[]{cross_x,cross_y};}if(point4[0]-point3[0]==0){double k1 = (point2[1]-point1[1])/(point2[0]-point1[0]);double b1 = point1[1]-point1[0]*k1;double cross_x = point3[0];double cross_y = k1*cross_x+b1;return new double[]{cross_x,cross_y};}double k1 = (point2[1]-point1[1])/(point2[0]-point1[0]);double b1 = point1[1]-point1[0]*k1;double k2 = (point4[1]-point3[1])/(point4[0]-point3[0]);double b2 = point3[1]-point3[0]*k2;double cross_x = (b1-b2)/(k2-k1);double cross_y = k1*cross_x+b1;return new double[]{cross_x,cross_y};}
}

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JAVA计算两条直线的交点(判断两条线段相交)

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本文标签:两条   线段   交点   直线   JAVA

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