交点"/>
【python】求两条直线的交点
理论推导:
def calc_abc_from_line_2d(x0, y0, x1, y1):a = y0-y1b = x1-x0c = x0*y1-x1*y0return a, b, cdef get_line_cross_point(line1, line2):a0, b0, c0 = calc_abc_from_line_2d(*line1)a1, b1, c1 = calc_abc_from_line_2d(*line2)D = a0*b1-a1*b0if D==0:return Nonex = (b0*c1-b1*c0)/Dy = (a1*c0-a0*c1)/Dreturn x, yline1 = [0, 0, 1, 1]
line2 = [0, 1, 1, 0]
print(get_line_cross_point(line1, line2))
(0.5, 0.5)Process finished with exit code 0
更多推荐
【python】求两条直线的交点
发布评论