尝试对计时器进行编程，以便用户只能在一定时间内输入单词

本文介绍了尝试对计时器进行编程，以便用户只能在一定时间内输入单词的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我正在尝试制作一个游戏，您只能输入 10 秒钟的单词.我试图创建一个多线程解决方案，但它不能正常工作.

I am trying to make a game where you can only enter words for 10 seconds. I tried to create a multithread solution but it doesn't work properly.

class timer extends Thread{//thread
public void run(){
    for(int i=10;i>=0;i--){
        System.out.print(i+" ");
        try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}
}

主要方法:

            timer t=new timer();
            t.start();
            while () {//not sure what to put in my while statement
                System.out.print("Guess a word on the board! ");
                if(test.CheckGame(scan.next())==true){
                    System.out.print("Good job! ");
                }
                else    
                    System.out.print("Guess again! ");
            }

本质上，在线程运行 10 秒并终止后，我希望它返回一个 break 语句，以便程序离开 while 循环.有什么建议?

essentially, after the thread goes for 10 seconds and terminates,I want it to return a break statement so the program leaves the while loop. Any suggestions?

推荐答案

这是一个简单的 Demo，可以让您了解如何使用 java.util.Timer .

Here is a simple Demo that would let you to know how to use java.util.Timer .

import java.util.Timer;
import java.util.TimerTask;
import java.util.Scanner;
class Tester 
{
    static long i = 0;
    public static void main(String[] args) throws Exception
    {
        Scanner scanner = new Scanner(System.in);
        System.out.println("You have only 10 seconds to find the result");
        System.out.println("What is the value of : 111111 X 111111 ");
        Timer timer = new Timer("Timer");
        timer.schedule(new TimerTask()
        {
            public void run()
            {
                if (i == 12345654321L)
                {
                    System.out.println("Congrats!! you guessed the write answer :)");
                }
                else
                {
                    System.out.println("Sorry Time is over. You couldn't guess the correct answer.");
                }
                System.exit(0);
            }
        },10 * 1000 , 1);
        while (true)
        {
            i = scanner.nextLong(); 
            if ( i == 12345654321L)
            {
                System.out.println("Congrats!! you guessed the write answer :)");
                System.exit(0);
            }
            else
            {
                System.out.println("Try next  guess :");
            }
        }
    }
}

编辑

因为我没有你的所有代码，所以我在这里发布了你根据我的基本假设回答的解决方案.不要使用线程.而是使用 java.util.Timer.您的代码如下所示:

Since I don't have your all code so I am posting here the solution for your answer on my basic assumption. Don't use Thread. Instead use java.util.Timer. Your code would look as follows:

static String input=" ";//created a static variable input to take input 
public static void main(String st[])
{
    Timer timer = new Timer("Timer");
    timer.schedule(new TimerTask()
    {
        public void run()
        {
            if (test.CheckGame(input))
            {
                System.out.println("Congrats!! you guessed the write answer :)");
            }
            else
            {
                System.out.println("Sorry Time is over. You couldn't guess the correct answer.");
            }
            System.exit(0);
        }
    },10 * 1000 , 1);//waits for 10 seconds
    while (true) 
    {
        System.out.print("Guess a word on the board! ");
        input = scan.next();
        if(test.CheckGame(input))
        {
            System.out.print("Good job! ");
            System.exit(0);
        }
        else
        {
            System.out.println("Bad Guess. Try again ");
        }
    }
}

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