多个正则表达式替换

本文介绍了多个正则表达式替换的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我对正则表达式感到困惑我认为当涉及到这些可怕的代码时，我会有阅读困难..无论如何，必须有一种更简单的方法来做到这一点 - （即在一行中列出一组替换实例） ， 任何人？在此先感谢。

I am boggled by regex I think I'm dyslexic when it comes to these horrible bits of code.. anyway, there must be an easier way to do this- (ie. list a set of replace instances in one line), anyone? Thanks in advance.

function clean(string) { string = string.replace(/\@~rb~@/g, '').replace(/}/g, '@~rb~@'); string = string.replace(/\@~lb~@/g, '').replace(/{/g, '@~lb~@'); string = string.replace(/\@~qu~@/g, '').replace(/\"/g, '@~qu~@'); string = string.replace(/\@~cn~@/g, '').replace(/\:/g, '@~cn~@'); string = string.replace(/\@-cm-@/g, '').replace(/\,/g, '@-cm-@'); return string; }

推荐答案

您可以定义一个通用函数，如果您可以在更多部分重用它，这将是有意义的你的代码是干的。如果你没有理由定义一个通用的代码，我只会压缩​​清除序列的部分，并保留其他部分替换它们。

You can define either a generic function, which would make sense if you can reuse it in more parts of your code, thus making it DRY. If you don't have reason to define a generic one, I would compress only the part which cleans sequences and leave the other replaces as they are.

function clean(string) { string = string.replace(/\@~rb~@|\@~lb~@|\@~qu~@|\@~cn~@|\@-cm-@/g, '') .replace(/}/g, '@~rb~@').replace(/{/g, '@~lb~@') .replace(/\"/g, '@~qu~@').replace(/\:/g, '@~cn~@') .replace(/\,/g, '@-cm-@'); return string; }

但请注意，此代码中的替换顺序已更改。虽然它似乎但它们可能不会影响结果。

But be careful, the order of the replacements were changed it in this code.. although it seems they might not affect the result.