强制 pandas 将列中的(1,2)解释为字符串而不是范围?

本文介绍了强制 pandas 将列中的(1,2)解释为字符串而不是范围?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在pandas Dataframe中有这种奇怪的行为.我在具有以下示例内容的列上使用.apply(single_seats_comma):(1,2).但是，它似乎以range(1,3)而不是字符串(1,2)的形式返回.其他行也有两个以上的条目，例如 (30,31,32).我有一个函数，该函数在,上分割并将括号中的每个值转换为新行，但是使用(x,x)则会中断.

I have this weird behaviour in a pandas Dataframe. I am using .apply(single_seats_comma) on a column with the following example content: (1,2). However, it seems to return it as range(1,3) instead of a string (1,2). Other rows have more than 2 entries as well, e.g. (30,31,32). I have a function which splits on , and converts each value in brackets into a new row however with (x,x) it breaks.

def single_seats_comma(row): strlist = str(row).split(',') strlist = filter(None, strlist) intlist = [] for el in strlist: intlist.append(int(el)) return intlist

应用"示例:

tickets['seats'][:1].apply(single_seats_comma)

def的错误输出为

ValueError: invalid literal for int() with base 10: 'range(1'

试图找到解决方案，我发现了这一点:

Trying to find a solution, I found this:

str(tickets['seats'][:1]) >>'0 (1, 2)\nName: seats, dtype: object' tickets['seats'][:1].values >> '[range(1, 3)]'

如果值只是1,2，则可在列上使用.

It works on a column if the values are just 1,2.

非常感谢任何帮助！

推荐答案

感谢所有贡献者，让我更接近解决方案.解决方案实际上很简单.

Thanks to all contributors to get me closer to a solution. The solution is actually quite simple.

挑战在于，大熊猫将(1,2)解释为范围而不是字符串.但是，目标是创建所有值的列表，最初是通过在'，'上分割字符串来实现的.不需要！

The challenge was that pandas interpreted (1,2) as range and not as string However, the target was to create a list of all values, originally by splitting a string on ','. Not needed!

list(range(1,2))已经完成了工作.这是示例和解决方案:

list(range(1,2)) does the job already. Here is the example and solution:

list(range(11, 17)) >> [11, 12, 13, 14, 15, 16] tickets['seats'][0] >> range(1, 3) list(alltickets['seats'][0]) >> [1, 2]

解决方法:

def single_seats_comma(row): strlist = list(row) return strlist tickets['seats'].apply(single_seats_comma)

或

tickets['seats'].apply(lambda row: list(row))