本文介绍了Python3,与列表重新匹配的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我读了这篇文章: stackoverflow/a/17090205/6426449
然后我列出了无法在Django中的用户名上使用的列表.
And I made a list that cannot be used on username in django.
列表: FORBIDDEN_USERNAME_LIST = ['admin','master','owner']
所以我做了这样的代码:
So I made a code like this :
views.py
def username_choice(request): if request.method == "POST": username = request.POST['username'] for item in forbidden.FORBIDDEN_USERNAME_LIST: match = re.search("r'\b"+item+"\b'", username) if match: return JsonResponse({'result': item + 'banned username'})但是似乎不起作用.
也许我认为, match = re.search("r'\ b" + item +"\ b'",用户名)这是问题.
Maybe I think, match = re.search("r'\b"+item+"\b'", username) Here is problem.
我该如何解决?
推荐答案您可以简单地在中使用:
forbidden = ['admin', 'master', 'owner'] username = request.POST['username'] match = [nm for nm in forbidden if nm in username] if match: # part of the username is in the forbidden list.IPython中的示例:
Example in IPython:
In [1]: forbidden = ['admin', 'master', 'owner'] In [2]: username = 'owner123' In [3]: match = [nm for nm in forbidden if nm in username] In [4]: match Out[4]: ['owner']更多推荐
Python3,与列表重新匹配
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