Python3，与列表重新匹配

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我读了这篇文章: stackoverflow/a/17090205/6426449

然后我列出了无法在Django中的用户名上使用的列表.

And I made a list that cannot be used on username in django.

列表: FORBIDDEN_USERNAME_LIST = ['admin'，'master'，'owner']

所以我做了这样的代码:

So I made a code like this :

views.py

def username_choice(request): if request.method == "POST": username = request.POST['username'] for item in forbidden.FORBIDDEN_USERNAME_LIST: match = re.search("r'\b"+item+"\b'", username) if match: return JsonResponse({'result': item + 'banned username'})

但是似乎不起作用.

也许我认为， match = re.search("r'\ b" + item +"\ b'"，用户名)这是问题.

Maybe I think, match = re.search("r'\b"+item+"\b'", username) Here is problem.

我该如何解决?

推荐答案

您可以简单地在中使用:

forbidden = ['admin', 'master', 'owner'] username = request.POST['username'] match = [nm for nm in forbidden if nm in username] if match: # part of the username is in the forbidden list.

IPython中的示例:

Example in IPython:

In [1]: forbidden = ['admin', 'master', 'owner'] In [2]: username = 'owner123' In [3]: match = [nm for nm in forbidden if nm in username] In [4]: match Out[4]: ['owner']