如何在python3中使用列表理解替换值?

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我想知道如何使用列表理解来替换列表的值.例如

I was wondering how would you can replace values of a list using list comprehension. e.g.

theList = [[1,2,3],[4,5,6],[7,8,9]] newList = [[1,2,3],[4,5,6],[7,8,9]] for i in range(len(theList)): for j in range(len(theList)): if theList[i][j] % 2 == 0: newList[i][j] = 'hey'

我想知道如何将其转换为列表理解格式.

I want to know how I could convert this into the list comprehension format.

推荐答案

您可以执行嵌套列表理解:

You can just do a nested list comprehension:

theList = [[1,2,3],[4,5,6],[7,8,9]] [[x if x % 2 else 'hey' for x in sl] for sl in theList]

返回

[[1, 'hey', 3], ['hey', 5, 'hey'], [7, 'hey', 9]]