为什么在@interface中声明对象在Xcode 4中使用@property时

本文介绍了为什么在@interface中声明对象在Xcode 4中使用@property时的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 @interface first : <NSObject> { NSString *myStr; /** I don't understand why declared this NSString *myStr. Even if not declare NSString *myStr, this codes work well. **/ } @property (nonatomic, retain) NSString *myStr; and Add @synthesize to first.m

如果我始终使用myStr属性，即self.myStr，是否不需要将myStr声明为实例变量是否正确?

Is it correct that I don't need to declare myStr as an instance variable if I always use the myStr property, i.e. self.myStr?

推荐答案

在现代运行时(带有合理版本的xcode，模拟器等)中，这没有什么区别，因为编译器会为您生成它.

In the modern runtime (with a reasonably recent version of xcode, simulator etc.) it makes no difference because the compiler generates it for you.

请注意，使用最新版本的LLVM，您甚至不需要合成;)

Note that with the newest version of LLVM you don't even need the synthesize ;)