多线卷曲命令

本文介绍了多线卷曲命令的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试修改使用Google Chrome开发工具捕获的卷曲请求。

I am trying to modify a curl request that was captured with Google Chrome Dev Tools.

这是命令的样子

curl "WEBSITE" -H "Host: WEBSITE" -H "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8" -H "Accept-Language: en-US,en;q=0.5" --compressed -H "Content-Type: multipart/form-data; boundary=---------------------------1184875127259" --data-binary "-----------------------------1184875127259"^ "Content-Disposition: form-data; name=""FORM1"""^ "FORM1DATA"^ "-----------------------------1184875127259"^ "Content-Disposition: form-data; name=""FORM2"""^ "FORM2DATA"^ "-----------------------------1184875127259"^ "Content-Disposition: form-data; name=""FORM3"""^ "FORM3DATA"^ "-----------------------------1184875127259"^ "Content-Disposition: form-data; name=""embed"""^ "true"^ "---------------------------1184875127259--"^ ""

表单＃是表单的名称，表单#Data 是我在表单中提交的数据。

Form# is the name of the form and Form#Data is the data I submitted in the forms.

我如何才能将这个单线卷曲请求复制到我的命令行中并让它与我的浏览器做同样的事情？

How would I make this be a single line curl request I can just copy into my command line and have it do the same thing that my browser did?

推荐答案

对多行输入使用 \ 转义字符

Use the \ escape character for multiline inputs

curl "WEBSITE" -H "Host: WEBSITE"\ -H "Accept: text/html,application/xhtml+xml\ ,application/xml;q=0.9,*/*;q=0.8"