python UTC时间减去5分钟

本文介绍了python UTC时间减去5分钟的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何在 Python 中将时间四舍五入 5 分钟?

How to round down a time 5 minutes in Python?

我有这个脚本，但我认为这可以更容易，而且整个小时的计算都出错了.当它是 22:03 时，它返回 21:95 而不是 21:55.

I have this script, but i think this can be easyer, and the full hours the calculation goes wrong. When its 22:03 it returns 21:95 instead of 21:55.

import datetime from datetime import date import time utc_datetime = datetime.datetime.utcnow() jaar = date.today().year maand = time.strftime("%m") dag = time.strftime("%d") uurutc = utc_datetime.strftime("%H") autc = utc_datetime.strftime("%M") minuututc = int(5 * round(float(autc)/5)-5) uur = time.strftime("%H") a = time.strftime("%M") minuut = int(5 * round(float(a)/5)-5) timestamp = ''.join(str(x) for x in [jaar, maand, dag, uurutc, minuututc]) print timestamp

代码实际应该做什么:

我们的本地时间是 UTC+2，但我只需要 UTC 时间，所以输出必须是 UTC.其次，时间需要在当前时间之前 5 分钟，然后向下取整.字符串的输出格式应为:YYYYMMDDHHMM.

Our local time is UTC+2, but i only need the UTC time, so the output must be in UTC. Second, the time needs to be 5 min before current time and then round down. The output format of the string should be: YYYYMMDDHHMM.

示例:

当地时间:12:53 > 输出脚本:10:45

local time: 12:53 > output script: 10:45

当地时间:17:07 > 输出脚本:15:00

local time: 17:07 > output script: 15:00

当地时间:08:24 > 输出脚本:06:15

local time: 08:24 > output script: 06:15

谁能帮我解决这个问题?

Who can help me with this out?

谢谢！

推荐答案

使用 datetime.timedelta:

from datetime import datetime, timedelta now = datetime.utcnow() rounded = now - timedelta(minutes=now.minute % 5 + 5, seconds=now.second, microseconds=now.microsecond) print rounded # -> 2014-04-12 00:05:00