运行时：
ls -la | ./countPar.sh 5收到错误：
ls -la | ./countPar.sh 5 awk：myawk.awk：6：filetime [$'$ colnumber'] ++; awk：myawk.awk：6：表达式中无效的字符''''$ <$ $ p？ $ colnumber必须替换为5，所以awk应该读取lsput的第5列。 Thanks。
解决方案您可以直接从命令行将变量传递到您的awk脚本。 b $ b
更改这一行：
filetime [$'$ colnumber'] ++;收件人：
FILETIME [colnumber] ++;并运行：
ls -al | awk -f ./myawk.awk -v colnumber = 5如果你真的想使用bash包装：
＃！/ bin / bash var1 = $ 1 awk -f myawk.awk colnumber = $ var1（与上面脚本相同的更改）
如果要使用环境变量，请使用：
＃！/ bin / bash export var1 = $ 1 awk -f myawk.awk和
filetime [ENVIRON [var1]] ++;（我真的不明白你的awk脚本的目的是什么，最后一部分可能简化为：
END {print filetime [colnumber]，colnumber;}解析 ls 的输出通常是一个坏主意。）
I have awk file:
#!/bin/awk -f BEGIN { } { filetime[$'$colnumber']++; } END { for (i in filetime) { print filetime[i],i; } }And bash script:
#!/bin/bash var1=$1 awk -f myawk.awkWhen I run:
ls -la | ./countPar.sh 5I receive error:
ls -la | ./countPar.sh 5 awk: myawk.awk:6: filetime[$'$colnumber']++; awk: myawk.awk:6: ^ invalid char ''' in expressionWhy? $colnumber must be replaced with 5, so awk should read 5th column of ls ouput. Thanks.
解决方案You can pass variables to your awk script directly from the command line.
Change this line:
filetime[$'$colnumber']++;To:
filetime[colnumber]++;And run:
ls -al | awk -f ./myawk.awk -v colnumber=5If you really want to use a bash wrapper:
#!/bin/bash var1=$1 awk -f myawk.awk colnumber=$var1(with the same change in your script as above.)
If you want to use environment variables use:
#!/bin/bash export var1=$1 awk -f myawk.awkand:
filetime[ENVIRON["var1"]]++;(I really don't understand what the purpose of your awk script is though. The last part could be simplified to:
END { print filetime[colnumber],colnumber; }and parsing the output of ls is generally a bad idea.)
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如何将bash参数传递给awk脚本？
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