如何在Swift中创建接口

本文介绍了如何在Swift中创建接口的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想快速创建类似接口的功能，我的目标是当我调用另一个类时假设我正在调用API，并且该类的响应我想反映到当前屏幕中，因此在android接口中用于实现但是我该如何快速使用呢?谁能帮我举个例子. android的代码在下面给出...

i want to create functionality like interface in swift, my goal is when i call another class suppose i'm calling API and the response of that class i want to reflect in to my current screen, in android interface is used to achieve but what should i use in swift for that? can anyone help me with example. the code for android is given below...

public class ExecuteServerReq { public GetResponse getResponse = null; public void somemethod() { getResponse.onResponse(Response); } public interface GetResponse { void onResponse(String objects); } } ExecuteServerReq executeServerReq = new ExecuteServerReq(); executeServerReq.getResponse = new ExecuteServerReq.GetResponse() { @Override public void onResponse(String objects) { } }

推荐答案

而不是界面swift拥有协议.

Instead of interface swift have Protocols.

协议定义了适合特定任务或功能的方法，属性和其他要求的蓝图.然后，该协议可以由类，结构或枚举采用，以提供这些要求的实际实现.满足协议要求的任何类型都被认为符合该协议.

A protocol defines a blueprint of methods, properties, and other requirements that suit a particular task or piece of functionality. The protocol can then be adopted by a class, structure, or enumeration to provide an actual implementation of those requirements. Any type that satisfies the requirements of a protocol is said to conform to that protocol.

让我们参加考试.

protocol Animal { func canSwim() -> Bool }

并且我们有一个确认此协议名称为Animal

and we have a class that confirm this protocol name Animal

class Human : Animal { func canSwim() -> Bool { return true } }

有关更多信息，请访问- developer .apple/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Protocols.html

for more go to - developer.apple/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Protocols.html