反转数组中的内容

本文介绍了反转数组中的内容的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一组要反转的数字.我相信我的代码中的函数是正确的，但我无法获得正确的输出.

I have an array of numbers that I am trying to reverse. I believe the function in my code is correct, but I cannot get the proper output.

输出为:10 9 8 7 6.为什么我不能得到另一半的数字?当我从计数中删除/2"时，输出显示为:10 9 8 7 6 6 7 8 9 10

The output reads: 10 9 8 7 6. Why can't I get the other half of the numbers? When I remove the "/2" from count, the output reads: 10 9 8 7 6 6 7 8 9 10

void reverse(int [], int); int main () { const int SIZE = 10; int arr [SIZE] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; reverse(arr, SIZE); return 0; } void reverse(int arr[], int count) { int temp; for (int i = 0; i < count/2; ++i) { arr[i] = temp; temp = arr[count-i-1]; arr[count-i-1] = arr[i]; arr[i] = temp; cout << temp << " "; } }

推荐答案

这就是我的方法:

#include <algorithm> #include <iterator> int main() { const int SIZE = 10; int arr [SIZE] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; std::reverse(std::begin(arr), std::end(arr)); ... }