我试图创建一个php可执行文件(一个phar文件)以生成一些文件,并且我想知道如何获取phar文件的真实路径(在phar文件代码内).
I am trying to create a php executable (a phar file) for generating some files, and I would like to know how to get the real path of the phar file (within the phar file code).
我想做的是在phar文件的同一级别中创建一个文件夹,然后在其中创建新文件,但是realpath(__DIR__.'/../')似乎不起作用.
What I want to do is to create a folder in the same level of the phar file and create the new files there, but realpath(__DIR__.'/../') does not seem to work.
谢谢
推荐答案如 stackoverflow/a/28775172/282601 __FILE__常量具有以下方案的完整路径:
As shown in stackoverflow/a/28775172/282601 the __FILE__ constant has the full path with the scheme:
phar:///home/cweiske/Dev/test/phar/test.phar/path/to/foo.php__DIR__与之类似:
phar:///home/cweiske/Dev/test/phar/test.phar/path/to因此,在调用realpath(__DIR__)时,您仍然具有phar://前缀,可防止您加载文件.
So when calling realpath(__DIR__) you still have the phar:// prefix that prevents you from loading the file.
您必须删除phar://方案以及.phar内部文件的路径,才能使用__DIR__获取phar位置.
You have to remove the phar:// scheme as well as the path of the file inside the .phar to get the phar location with __DIR__.
Phar::running(false) 容易得多,它只是返回路径:
Much easier is Phar::running(false), which simply returns the path:
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