为类重载运算符new

本文介绍了为类重载运算符new的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

当我们重载一个类的新运算符时，我们将该函数声明为一个成员函数。 例如：

When we overload new operator of a class, we declare the function as a member function. For eg:

class OpNew { public: OpNew() { cout << "OpNew::OpNew()" << endl;} void* operator new(size_t sz) { cout << "OpNew::new: " << sz << " bytes" << endl; return ::new char[sz]; } };

语句 OpNew * obj = new OpNew 在发动机罩下工作？因为重载的新是OpNew类的成员而不是静态的。那么编译器如何保证这个调用 new 成功函数成功？

How does the statement OpNew *obj = new OpNew work under the hood ? as overloaded new is a member of OpNew class not a static. So how does compiler ensure this call to new member function succeeds?

推荐答案

运算符new（）或 ]

An operator new() or operator new[]() for a class is always a static class member, even if it is not declared with the keyword static.

类 T 的任何分配函数都是静态成员（即使没有显式声明 static ）。 / p>

Any allocation function for a class T is a static member (even if not explicitly declared static).