$结果= mysql

本文介绍了$结果= mysql_query()的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我是php/mysql的新手，所以如果我做的过时了，请在这里原谅我的知识水平，并随时将我引向一个更好的方向.

I am brand new to php/mysql, so please excuse my level of knowledge here, and feel free to direct me in a better direction, if what I am doing is out of date.

我正在从数据库中提取信息以填写登录页面.布局以左侧的图片和右侧的标题开始.在这里，我使用查询来检索页面标题文本:

I am pulling in information from a database to fill in a landing page. The layout starts with an image on the left and a headline to the right. Here, I am using the query to retrieve a page headline text:

<?php $result = mysql_query("SELECT banner_headline FROM low_engagement WHERE thread_segment = 'a3'", $connection); if(!$result) { die("Database query failed: " . mysql_error()); } while ($row = mysql_fetch_array($result)) { echo $row["banner_headline"]; } ?>

这很好用，但现在我想在 img alt 标签内复制该标题文本.在alt标记内复制此查询信息的最佳方法是什么?我可以使用任何简短的代码吗?还是仅将代码复制到alt标记中并运行两次就更好了?

This works great, but now I want to duplicate that headline text inside the img alt tag. What is the best way to duplicate this queries information inside the alt tag? Is there any abbreviated code I can use for this, or is it better to just copy this code inside the alt tag and run it twice?

感谢您的见解！

推荐答案

正如评论所说，您正在使用不推荐使用的函数，但是要回答您的问题，您应该声明一个变量，以在从数据库，以便您可以随时使用它.

You are, as the comment says, using deprecated functions, but to answer your question, you should declare a variable to hold the value once your retrieve it from the database so that you can use it whenever your want.

<?php $result = mysql_query("SELECT banner_headline FROM low_engagement WHERE thread_segment = 'a3'", $connection); if(!$result) { die("Database query failed: " . mysql_error()); } $bannerHeadline = ""; while ($row = mysql_fetch_array($result)) { $bannerHeadline = $row["banner_headline"]; } echo $bannerHeadline; //use this wherever you want ?>