Java长号太大错误？

本文介绍了Java长号太大错误？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

为什么我的int号太大而long被分配到min和max？

Why do I get an int number is too large where the long is assigned to min and max?

/* long: The long data type is a 64-bit signed two's complement integer. It has a minimum value of -9,223,372,036,854,775,808 and a maximum value of 9,223,372,036,854,775,807 (inclusive). Use this data type when you need a range of values wider than those provided by int. */ package Literals; public class Literal_Long { public static void main(String[] args) { long a = 1; long b = 2; long min = -9223372036854775808; long max = 9223372036854775807;//Inclusive System.out.println(a); System.out.println(b); System.out.println(a + b); System.out.println(min); System.out.println(max); } }

推荐答案

全部java中的文字数字默认为 ints ，其范围 -2147483648 至 2147483647 包含。

All literal numbers in java are by default ints, which has range -2147483648 to 2147483647 inclusive.

您的文字超出此范围，因此要进行此编译，您需要指明它们 long 文字（即后缀 L ）：

Your literals are outside this range, so to make this compile you need to indicate they're long literals (ie suffix with L):

long min = -9223372036854775808L; long max = 9223372036854775807L;

请注意，java支持大写 L 和小写 l ，但我建议不使用小写 l ，因为它看起来像 1 ：

Note that java supports both uppercase L and lowercase l, but I recommend not using lowercase l because it looks like a 1:

long min = -9223372036854775808l; // confusing: looks like the last digit is a 1 long max = 9223372036854775807l; // confusing: looks like the last digit is a 1

Java语言规范相同的

如果整数文字后缀为ASCII字母L或l（ell），则整数文字的长度为long;否则它的类型为int（§4.2.1）。

An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int (§4.2.1).