本文介绍了并行ForEach在生成之前等待500毫秒的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这种情况:
var tasks = new List<ITask> ... Parallel.ForEach(tasks, currentTask => currentTask.Execute() );是否可以指示PLinq等待500ms,直到产生下一个线程?
Is it possible to instruct PLinq to wait for 500ms before the next thread is spawned?
System.Threading.Thread.Sleep(5000); 推荐答案您正在使用 Parallel.Foreach 完全错误,您应该制作一个特殊的枚举器,将其速率限制为每500毫秒获取一次数据
You are using Parallel.Foreach totally wrong, You should make a special Enumerator that rate limits itself to getting data once every 500 ms.
由于您未提供任何详细信息,因此我对您的 DTO 的工作方式进行了一些假设.
I made some assumptions on how your DTO works due to you not providing any details.
private IEnumerator<SomeResource> GetRateLimitedResource() { SomeResource someResource = null; do { someResource = _remoteProvider.GetData(); if(someResource != null) { yield return someResource; Thread.Sleep(500); } } while (someResource != null); }这就是您的并购外观
Parallel.ForEach(GetRateLimitedResource(), SomeFunctionToProcessSomeResource);更多推荐
并行ForEach在生成之前等待500毫秒
发布评论