做一会儿没用

本文介绍了做一会儿没用的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

#include <stdio.h> #include <stdlib.h> int main(void) { char again; do{ printf("insert y or Y to repeat"); fflush(stdout); scanf("%c",&again); }while(again=='y'||again=='Y'); }

我编写了这段代码以创建一个循环，当再次插入y或Y时，它会再次执行此工作，但是没有用.当我第一次输入y时，循环结束. [edit]代码块已修复[/edit]

i wrote this code to create a loop that when insert y or Y do the job again but did not work.when i enter first y the loop be end. [edit]code blocks fixed[/edit]

推荐答案

您按了y；和"\ n"(输入).两个字符. 您可以对其进行修改 you pressed ''y; and ''\n''(Enter).two chars. you can modify it #include <stdio.h> #include <stdlib.h> int main(void) { char again; do{ printf("insert y or Y to repeat"); fflush(stdout); scanf("%c",&again); getchar(); }while(again=='y'||again=='Y'); }

我工作.但这并不像您想象的那样起作用. 作为一种简单的解决方法，您可以使用字符串而不是char作为scanf的输入，例如 I works. But it doesn''t work the way you think it does. As a simple workaround you may use a string instead of char as input for scanf, e.g. #include <stdio.h> #include <stdlib.h> int main(void) { char buf[0x100]; do{ printf("insert y or Y to repeat"); fflush(stdout); while (scanf("%s",buf) != 1); }while(buf[0]=='y'|| buf[0]=='Y'); }

[更新] 试试这个:

[Update] try this one:

#include <stdio.h> #include <stdlib.h> int scan_frac(int *num,int *denom); int main(void){ int num1,denom1; char buf[0x100]; do{ if ( scan_frac(&num1,&denom1) == 2) { if ( denom1 != 0) { printf("%d/%d = %g\n", num1, denom1, ((double)num1)/denom1); fflush(stdout); } } printf("insert (y) to do another division\n"); fflush(stdout); scanf("%s", buf); }while(buf[0]=='y'||buf[0]=='Y'); return 0; } int scan_frac(int *num,int *denom){ int values; int n,dn; printf("insert numerator and denominator (use blank as separator): "); fflush(stdout); values = scanf("%d %d",&n,&dn); *num=n; *denom=dn; return values; }

[/Update]

[/Update]

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