使用trait绑定动态创建类

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因此，我创建了一些traits来使用，例如：tItem_Epic，我想要使用我的项目中的traits，并且对于多个inheriance我想使用traits。 tItem_Weapon，Item_Driver

当我为Sword创建新类时，我认为我可以使用eval创建类：

<？php function new_item_class（$ type） { eval（'class Item _'。ucfirst（$ type）。'extends Item_Driver { use tItem_Epic，tItem_Weapon;}'）; } ？>

这是一个例子。还有一些参数改变了eval的过程（如：项目质量等）。

这是否会减慢进度？或者我应该为每个项目类型创建一个文件，并在需要时调用它们？

解决方案

您可以生成磁盘上的文件，这可能是IDE的一个好处，因为他们可以解析那些

对于PHP来说， eval 之间没有太大的区别）和 include （磁盘上的文件示例）。

我个人更喜欢文件，因为它比那些魔法类更直接。我不会寻找性能的原因来决定。你谈论的那种表演是短视的，因为它没有定义你谈论的是什么样的表演，特别是因为你还没有陷入瓶颈。

I want to make use of traits in my project, and for multiple inheriance I want to use traits.

So I created some traits to use eg: tItem_Epic, tItem_Weapon, Item_Driver

When I create new class for Sword, I thought I could use eval to create class:

<?php function new_item_class($type) { eval('class Item_'.ucfirst($type).' extends Item_Driver { use tItem_Epic, tItem_Weapon; }'); } ?>

This is an example. There are some more parameters that change the course of eval (like: item quality, etc.).

Does this slow down the progress? Or should I create a file for every item type and call them when needed? which one will be faster?

解决方案

You could generate the files on disk which could be a benefit with IDEs as they can parse those files as well and it's less magic.

For PHP there is not much difference between eval (your code-exmaple) and include (example with files on disk). So do what pleases you I'd say.

I personally prefer files because it's more direct than those magic classes. And I would not look for "performance" reasons to decide that. The kind of performance you talk about is short-sighted as it remains undefined about which kind of performance you talk about and especially because you did not yet run into a bottleneck.