本文介绍了将具有可变列数的文本文件读取到列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个像这样的文件:
I have a file like this:
mylist.txt 234984 10354 41175 932711 426928 1693237 13462此文件的每一行具有不同数量的元素,每行最少1个元素. 我想将其读入这样的列表中:
Each line of this file has different number of elements, minimum of 1 element per line. I would like to read it into a list like this:
> print(head(mylist,2)) [[1]] [1] 234984 10354 41175 932711 426928 [[2]] [1] 1693237 13462推荐答案
假定空格是定界符:
fc <- file("mylist.txt") mylist <- strsplit(readLines(fc), " ") close(fc)
如果值由多个空格定界(一个/或不一致的方式),则可以将定界符与正则表达式匹配:
If the values are delimited by several spaces (an/or in unconsistent way), you can match delimiter with regular expression:
mylist.txt 234984 10354 41175 932711 426928 1693237 13462 fc <- file("mylist.txt") mylist <- strsplit(readLines(fc), " +") close(fc)编辑#2
由于strsplit返回字符串,因此您需要将数据转换为数字(这很简单):
And since strsplit returns strings, you need to convert your data to numeric (that's an easy one):
mylist <- lapply(mylist, as.numeric)更多推荐
将具有可变列数的文本文件读取到列表
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