在 Python 3.3.2 中计算短语频率

本文介绍了在 Python 3.3.2 中计算短语频率的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我一直在检查网络上的不同来源，并尝试了各种方法，但只能找到如何计算唯一词的频率，而不是唯一短语的频率.到目前为止，我的代码如下:

I have been examining different sources on the web and have tried various methods but could only find how to count the frequency of unique words but not unique phrases. The code I have so far is as follows:

import collections import re wanted = set(['inflation', 'gold', 'bank']) cnt = collections.Counter() words = re.findall('w+', open('02.2003.BenBernanke.txt').read().lower()) for word in words: if word in wanted: cnt [word] += 1 print (cnt)

如果可能，我还想计算一下本文中使用中央银行"和高通胀"这两个词的次数.感谢您提供的任何建议或指导.

If possible, I would also like to count the number of times the phrases 'central bank' and 'high inflation' is used in this text. I appreciate any suggestion or guidance you can give.

推荐答案

首先，这就是我将如何生成您所做的 cnt(以减少内存开销)

First of all, this is how I would generate the cnt that you do (to reduce memory overhead)

def findWords(filepath): with open(filepath) as infile: for line in infile: words = re.findall('w+', line.lower()) yield from words cnt = collections.Counter(findWords('02.2003.BenBernanke.txt'))

现在，关于短语的问题:

Now, on to your question about phrases:

from itertools import tee phrases = {'central bank', 'high inflation'} fw1, fw2 = tee(findWords('02.2003.BenBernanke.txt')) next(fw2) for w1,w2 in zip(fw1, fw2)): phrase = ' '.join([w1, w2]) if phrase in phrases: cnt[phrase] += 1

希望能帮到你