尺寸大小计算"/>
C++尺寸大小计算
英文题目(老师给的原版题目):
Hat size=weight in pounds divided by height in inches and all that multiplied by 2.9。
Jacket size(chest in inches)=height times weight divided by 288 and then adjusted by adding 1/8 of an inch for each 10 years over age 30.(Note that the adjustment only takes place after a full 10 years.So,there is no adjustment for ages 30 through 39,but 1/8 of an inch is added for age 40.)
Waist in inches=weight divided by 5.7 and then adjusted by adding 1/10 of an inch for each 2 years over age 28.(Note that the adjustment only takes place after a full 2 years.So,there is no adjustment for age 29,but 1/10 of an inch is added for age 30.)
Use functions for each calculation.Your program should allow the user to repeat this calculation as often as the user wishes.
中文题目(简单翻译了一下):
帽子大小=体重(磅)除以身高(英寸)所有这些乘以2.9。
夹克尺寸(胸围英寸)=身高乘以体重除以288,然后对30岁以上的每10岁增加1/8英寸进行调整。(请注意,调整只在整整10年之后进行。因此,30到39岁的年龄没有调整,但40岁的年龄会增加1/8英寸。)
腰围(英寸)=体重除以5.7,然后对28岁以上的每2岁增加1/10英寸进行调整。(请注意,调整只在整整两年之后进行。因此,29岁的年龄没有调整,但30岁的年龄增加了1/10英寸。)
对每个计算使用函数。您的程序应该允许用户按照自己的意愿重复这个计算。
代码:
#include <iostream>
#include <stdlib.h>
using namespace std;float HatSize(float Weight,float Height){float size,temp;temp=Weight/Height;size=temp*2.9;return size;
}float JacketSize(float Weight,float Height,int Age){float temp,size;temp=Height*Weight;size=temp/288;if(Age<=30){return size;}else{int temp1;float temp2,temp3;temp1=Age-30;temp2=temp1/10;temp3=temp2/8;size+=temp3;return size;}
}float WaistSize(float Weight,int Age){float size;size=Weight/5.7;if(Age<=28){return size;}else{int temp1;float temp2,temp3;temp1=Age-28;temp2=temp1/2;temp3=temp2/10;size+=temp3;return size;}
}int main() {float height,weight,hatsize,jacketsize,waistsize;int age;char ch;do{cout<<"请输入身高(英寸):"<<endl;cin>>height;cout<<"请输入体重(磅):"<<endl;cin>>weight;cout<<"请输入年龄:"<<endl;cin>>age;hatsize=HatSize(weight, height);jacketsize=JacketSize(weight, height, age);waistsize=WaistSize(weight, age);cout<<"你的帽子尺寸是:"<<hatsize<<"英寸"<<endl;cout<<"你的夹克尺寸是:"<<jacketsize<<"英寸"<<endl;cout<<"你的腰围是:"<<waistsize<<"英寸"<<endl;cout<<"是否继续查询?(y 或 n)"<<endl;cin>>ch;if(ch!='y' && ch!='n'){cout<<"输入错误,程序退出!"<<endl;exit(0);}}while(ch!='n');cout<<"退出成功!"<<endl;return 0;
}
比较基础的C++题目,适合初学者。
更多推荐
C++尺寸大小计算
发布评论