1672
1672. 最富有客户的资产总量
You are given an m x n integer grid(整数网格) accounts where accounts[i][j] is the amount of money the ith customer has in the jth bank. Return the wealth that the richest customer has.
A customer’s wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
Example 1:
Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.
Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17
Constraints:
m == accounts.length
n == accounts[i].length
1 <= m, n <= 50
1 <= accounts[i][j] <= 100
我的解题
class Solution {public int maximumWealth(int[][] accounts) {int max=-1;int result[]=new int[accounts.length];for(int i=0;i<accounts.length;i++){for(int j=0;j<accounts[i].length;j++){result[i]+=accounts[i][j];}if(result[i]>max){max=result[i];}}return max;}
}
我的解题思路
二维数组,每一行代表一个客户的所有资产,通过遍历数组,把每层的资产 result[i]+=accounts[i][j];
赋值给那一层对应的客户result[i]
,然后每一层加完之后比较下是不是最大值,如果>max的话就
max=result[i]
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