python爬app ios

编程入门 行业动态 更新时间:2024-10-12 05:54:53

<a href=https://www.elefans.com/category/jswz/34/1770869.html style=python爬app ios"/>

python爬app ios

该楼层疑似违规已被系统折叠 隐藏此楼查看此楼

RT,随便找了个网站练习,爬取APP信息然后写入数据库。新手写的比较乱,请见谅。源码如下:

#encoding:utf-8

import requests,io,sys,re,pymysql

from bs4 import BeautifulSoup

sys.stdout = io.TextIOWrapper(sys.stdout.buffer,encoding='gb18030')

url=''

headers={

'User-Agent':'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2883.87 UBrowser/6.2.4094.1 Safari/537.36'

}

wants={}

def spider_bang(classs):

response=requests.get(url,headers=headers)

soup=BeautifulSoup(response.text,'lxml')

pays=soup.find_all('td',class_=classs)

tits=[]

leis=[]

prices=[]

for pay in pays:

titles=pay.find_all('h4')

ps1s=pay.find_all('p')[0].text.split(':',1)[1]

ps2s=pay.find_all('p')[1].text.encode('utf-8').decode('utf-8')

ps2s=re.findall('价格:¥(.*?).00',ps2s)

wants['是否收费']=classs

for title in titles:

title=title.text

wants['APP名称']=title

wants['APP类别']=ps1s

for ps2 in ps2s:

wants['价格']=ps2

print(wants)

db = pymysql.connect(host='localhost', user='root', password='xxxxxxx', port=3306, db='mysql')

cursor = db.cursor()

table = 'topapp'

keys = ', '.join(wants.keys())

values = ', '.join(['%s'] * len(wants))

sql = 'INSERT INTO {table}({keys}) VALUES ({values})'.format(table=table, keys=keys, values=values)

if cursor.execute(sql, tuple(wants.values())):

print("Succesful")

dbmit()

if __name__ == '__main__':

classss=[

'pay',

'free',

'all'

]

for classs in classss:

spider_bang(classs)

更多推荐

python爬app ios

本文发布于:2024-02-06 14:14:49,感谢您对本站的认可!
本文链接:https://www.elefans.com/category/jswz/34/1749636.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
本文标签:python   app   ios

发布评论

评论列表 (有 0 条评论)
草根站长

>www.elefans.com

编程频道|电子爱好者 - 技术资讯及电子产品介绍!