段位计算"/>
2649: 段位计算
2649: 段位计算
Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 152 Solved: 94
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Description
输入分数score,根据以下信息输出段位
青铜:0<score<=1200 Brass
白银:1200<score<=1450 Silver
黄金:1450<score<=1700 Gold
白金:1700<score<=2000 Platinum gold
钻石:2000<score Diamonds
Input
输入一个分数
Output
输出对应段位
Sample Input
1000
Sample Output
Brass
AC代码:#include <stdio.h>
#include <stdlib.h>int main()
{int score;scanf("%d",&score);if(score>0&&score<=1200)printf("Brass\n");if(score>1200&&score<=1450)printf("Silver\n");if(score>1450&&score<=1700)printf("Glod\n");if(score>1700&&score<=2000)printf("Platinum gold\n");if(score>2000)printf("Diamonds\n");return 0;
}
#include <stdio.h>
#include <stdlib.h>int main()
{int score;scanf("%d",&score);if(score>0&&score<=1200)printf("Brass\n");if(score>1200&&score<=1450)printf("Silver\n");if(score>1450&&score<=1700)printf("Glod\n");if(score>1700&&score<=2000)printf("Platinum gold\n");if(score>2000)printf("Diamonds\n");return 0;
}
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2649: 段位计算
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