PythonChanllenge第四关：Linkedlist

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PythonChanllenge第四关：Linkedlist

.php

源代码中的提示：

<a href="linkedlist.php?nothing=12345"><img src="chainsaw.jpg" border="0"/></a>

import urllib.request
import renextno = 12345for i in range(500):page = urllib.request.urlopen(".php?nothing=%s" % (nextno))text = page.read().decode("utf-8")nextno = re.search('and the next nothing is (\d+)', text)if nextno:nextno = nextno.groups()[0]print(nextno+'\n')else:print(text)break