零花钱"/>
John的零花钱
水题,思路就是前缀和的模板
//前缀和
#include<iostream>
using namespace std;typedef long long LL;
const int N = 1e6 + 10;
LL num[N];
LL sum[N];
LL n, m;
LL L, R;int main()
{cin >> n;for(int i = 1;i <= n; i ++){cin >> num[i];sum[i] = sum[i - 1] + num[i];}cin >> m;for(int i = 1; i <= m; i ++){cin >> L >> R;cout << (sum[R] - sum[L - 1]) << endl;}return 0;
}
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John的零花钱
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