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之字形打印矩阵
#include<iostream>
#define MAXROW 3
#define MAXCOL 4
using namespace std;
//打印之字形矩阵
//压中的点是每条对角线最右上的点(tR,tC)和最左下(dR,dC)的点
//右上点的移动逻辑:每次往左移动,移动不了了往下移动
//左下点的移动逻辑:每次往下移动,移动不了了往右移动
//upToDown:从上往下
void printDiagonal(int m[][MAXCOL],int tR,int tC,int dR, int dC, bool upToDown)
{if(upToDown){while(tR<=dR)cout<<m[tR++][tC--]<<"\t";}else{while(dR>=tR)cout<<m[dR--][dC++]<<"\t";}
}void printSpecialMatrix(int m[][MAXCOL])
{cout<<"==============NEW MATRIX=============="<<endl;int tR=0,tC=0;int dR=0,dC=0;int endR = MAXROW-1,endC = MAXCOL-1;bool upToDown = false;while(tR <= endR){printDiagonal(m,tR,tC,dR, dC, upToDown);tR = tC == endC ? tR + 1 : tR;tC = tC == endC ? tC : tC + 1;dC = dR == endR ? dC + 1 : dC;dR = dR == endR ? dR : dR + 1;upToDown = !upToDown;}cout<<endl;}void printMatrix(int m[][MAXCOL])
{cout<<"==============OLD MATRIX=============="<<endl;for(int i=0;i<MAXROW;i++){for(int j=0;j<MAXCOL;j++)cout<<m[i][j]<<"\t";cout<<endl;}}int main()
{int matrix[MAXROW][MAXCOL] = {{1,2,3,4},{5,6,7,8},{9,10,11,12}};printMatrix(matrix);printSpecialMatrix(matrix);return 0;
}
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之字形打印矩阵
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