vs2019利用EasyX实现反弹球消砖块

编程入门 行业动态 更新时间:2024-10-07 14:21:45

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vs2019利用EasyX实现反弹球消砖块

这里是引用
Hello,大家好我是“是令狐冲啊”来自安徽,现在在西安读书,很高兴能够利用csdn这个平台分享自己编程时的感想与问题,我热爱编程,热爱代码,努力学习,希望自己变得更好。

vs2019利用EasyX实现反弹球消砖块

目前还是一名小白,下面这个代码还存在一些bug,但是还在陆续改进中,希望大家给予批评和指正,我会不断改进滴。

#include<graphics.h>
#include<conio.h>
#define Width 640//初始化游戏画面的尺寸
#define High 480
#define Brick_num 10//砖头的个数
int isBrickExisted[Brick_num];//判断每个砖块是否存在,1为存在,0为不存在
int brick_high, brick_width;//定义砖头的高和宽度
int ball_x = Width / 2;//小球的中心坐标
int ball_y = High / 2;//小球的中心坐标
int radius = 20;//小球的半径
int bar_x = Width / 2;//挡板的中心坐标
int bar_high = High / 20;//挡板的高度和宽度
int bar_width = Width / 5;
int bar_y = High - bar_high / 2;
int bar_left = bar_x - bar_width / 2;//挡板左端点x
int bar_right = bar_x + bar_width / 2;//挡板右端点x
int bar_top = bar_y - bar_high / 2;//挡板顶点
int bar_bottom = bar_y + bar_high / 2;//挡板最低处
int ball_vx = 1, ball_vy = 1;//小球的速度
void startup()//数据的初始化
{brick_high = High / Brick_num;brick_width = Width / Brick_num;int i;for (i = 0; i < Brick_num; i++)isBrickExisted[i] = 1;initgraph(Width, High);BeginBatchDraw();
}
void clean()//消除画面
{setcolor(BLACK);//绘制黑线,黑色填充的圆setfillcolor(BLACK);fillcircle(ball_x,ball_y,radius);bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黑线黑色填充的挡板int i;int brick_left, brick_right, brick_top, brick_bottom;for (i = 0; i < Brick_num; i++){brick_left = i * brick_width;brick_top = 0;brick_right = brick_left + brick_width;brick_bottom = brick_high;if (isBrickExisted[i] == 0)//如果砖块等于0,砖块绘制成黑色fillrectangle(brick_left,brick_top,brick_right,brick_bottom);}
}
void show()
{//显示画面setcolor(YELLOW);setfillcolor(GREEN);fillcircle(ball_x, ball_y, radius);//绘制黄线,绿色填充的圆bar(bar_left, bar_top, bar_right, bar_bottom);int brick_left, brick_right, brick_top, brick_bottom;int i;for (i = 0; i < Brick_num; i++){brick_left = i * brick_width;brick_top = 0;brick_right = brick_left + brick_width;brick_bottom = brick_high;if (isBrickExisted[i])//判断砖块是否存在,若存在,绘制砖块{setcolor(WHITE);setfillcolor(RED);fillrectangle(brick_left, brick_top, brick_right, brick_bottom);}}FlushBatchDraw();Sleep(3);//延时
}
void updateWithoutInput()
{//判断挡板是否和小球发生碰撞,小球反弹if (((ball_y + radius >= bar_top) && (ball_y + radius < bar_bottom - bar_high/3 ) || (ball_y - radius <= bar_bottom) && (ball_y - radius > bar_top - bar_high / 3)))if ((ball_x <= bar_right) && (ball_x >= bar_left))ball_vy = -ball_vy;//更新小圆的坐标ball_x = ball_x + ball_vx;ball_y = ball_y + ball_vy;//小球和边界碰撞if ((ball_x <= radius) || (ball_x + radius >= Width))ball_vx = -ball_vx;if ((ball_y <= radius) || (ball_y + radius >= High))ball_vy = -ball_vy;//判断小球是否和砖块碰撞int brick_left, brick_right, brick_top, brick_bottom;int i;for (i = 0; i < Brick_num; i++){if (isBrickExisted[i]){brick_left = i * brick_width;brick_right = brick_left + brick_width;brick_bottom = brick_high;if ((ball_y == brick_bottom + radius) && (ball_x >= brick_left) &&( ball_x <= brick_right)){isBrickExisted[i] = 0;ball_vy = -ball_vy;}}}
}
void updateWithInput()
{char input;if (_kbhit())//通过用户的输入改变挡板的位置{input = _getch();if (input == 'a' && bar_left >=0){bar_x = bar_x - 15;bar_left = bar_x - bar_width / 2;bar_right = bar_x + bar_width / 2;}if (input == 's' && bar_bottom <High){bar_y = bar_y + 15;bar_top = bar_y - bar_high / 2;bar_bottom = bar_y+ bar_bottom / 2;}if (input == 'd' && bar_right <Width){bar_x = bar_x +15;bar_left = bar_x - bar_width / 2;bar_right = bar_x + bar_width / 2;}if (input == 'w' && bar_top > 0){bar_y = bar_y -15;bar_top = bar_y - bar_high / 2;bar_bottom = bar_y + bar_bottom / 2;}}
}
void gameover()
{EndBatchDraw();closegraph();
}
int main()
{startup();while (1){clean();updateWithoutInput();updateWithInput();show();}gameover();return 0;
}

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vs2019利用EasyX实现反弹球消砖块

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