19/9/26今日工事.Linux C++

工事.Linux C++"/>

19/9/26今日工事.Linux C++

（1）输入十个整数，输出十个整数的和

#include <iostream>
#include <cstdlib>
using namespace std;//没有在for后面加花括号，导致一直出现最后一个输入的数与sum相加的情况
int main()
{int a, sum =4,i;cout << "Please input 10 number:\n";for(i=0;i<5;i++){cin >> a;sum =sum+a;}cout << sum << "\n";return 0;
}

（2）输入存款金额，输入年利率，金额精确到分，一年期满的本金和利息总额

//如何精确到分，两种方式，一种是数精确到小数点后两位，一种是输出时精确到小数点后两位

/*数精确到小数点后两位

double c;
c = ((double)(int)((a+0.005)*100))/100;

*/

/*输出时精确到小数点后两位

    float a = 5.666;
    //第一种方式，从根本改变输出流
     cout<<setiosflags(ios::fixed)<<setprecision(2)<<a<<endl;
     //第一种方式，常规型 
    cout<<setprecision(2)<<fixed<<a<<endl;    
    //第三种方式，全局整体型
    cout.precision(2);
    cout<<a<<endl;   */

#include <iostream>
#include <cstdlib>
#include <iomanip>
using namespace std;//double two precision
//<iomanip>
int main()
{double a,b,c,d,e;cout << "Please input your deposit amount"  << ".\n";cin >> a;c = ((double)(int)((a+0.005)*100))/100;cout <<  " Your deposit amount is "<<c<<"RMB\n";cout << "Please input your Annual interst rate\n";cin >> b;cout << " Your Annual interst rate "<< b <<"%\n";b = b / 100;d = c*b;cout << " Your Annual interst "<< d <<"RMB\n";e = c + d;e = ((double)(int)((e+0.005)*100))/100;cout << " Your money "<< e <<"RMB\n";return 0;
}