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Java模拟获取随机车牌号的两种方式
通过简单的几行代码,模拟用户选车牌的业务场景,这边只是简单的获取随机车牌,没有任何业务交互!这边提供了2种方式获取随机车牌,首先是定义好字母数组和车牌数组,方式一是每个字符都是随机获取字母或数字,方式二是把字母和数字都放在集合种,每次都打乱集合的顺序,获取集合的前5个元素。个人觉得方式一更好些!
有兴趣的可以做一个延伸,例如:显示过的再一次执行的时候就直接过滤掉等
以下是源码:
public class CarNumberController {private static Random random = new Random();private static final String[] arr1 = {"A","B","C","D","E","F","G","H","J","K","L","M","N","P","Q","R","S","T","U","V","W","X","Y","Z"};private static final String[] arr2 = {"0","1","2","3","4","5","6","7","8","9"};private static final boolean[] arr3 = {false,true};//获取随机字符(字母或数字)public static String getSingleStr(boolean flag){if (flag) {return arr1[random.nextInt(arr1.length)];} else {return arr2[random.nextInt(arr2.length)];}}//方式一public static String method1(){StringBuilder sb = new StringBuilder();sb.append("苏U");for (int j = 0; j < 5; j++) {sb.append(getSingleStr(arr3[random.nextInt(arr3.length)]));}return sb.toString();}//方式二public static String method2(){List<String> list = new ArrayList<>();list.addAll(Arrays.asList(arr1));list.addAll(Arrays.asList(arr2));Collections.shuffle(list);StringBuilder sb = new StringBuilder();sb.append("苏U");for (int i = 0; i < 5; i++) {sb.append(list.get(i));}return sb.toString();}public static void main(String[] args) {List<String> list = new ArrayList<>(50);for (int i = 0; i < 50; i++) {list.add(method1());
// list.add(method2());}System.out.println(list);}
}
运行结果如下:
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Java模拟获取随机车牌号的两种方式
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