LeetCode 824： （C++）山羊拉丁文

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LeetCode 824： （C++）山羊拉丁文

太久没有写过LeetCode啦，今天刚好突然想起来，就找了道题目写一下，这次是用C++写的，因为最近在复习C++，正好这道题也简单，就写了一下，可能写的不咋样，大家就参考参考就行~

题目：

我把一些操作都分别用了不同的函数来写，应该也好理解，就不写详细思路了，应该都可以很容易看出来，这里有一个要注意的点就是 a e i o u不光是小写，还有大写也是属于同一种情况，加上就可以了

代码：

#include<iostream>
using namespace std;
class Solution {
public:int count = 0;string add(string subSentence) {subSentence += "ma";for (int i = 0; i < count; i++) {subSentence += "a";}return subSentence;}string change(string subSentence) {if (subSentence[0] == 'a' || subSentence[0] == 'e' || subSentence[0] == 'i' || subSentence[0] == 'o' || subSentence[0] == 'u' || subSentence[0] == 'A' || subSentence[0] == 'E' || subSentence[0] == 'I' || subSentence[0] == 'O' || subSentence[0] == 'U') {subSentence = add(subSentence);}else {// 移动字母再添加char c = subSentence[0];subSentence = subSentence.substr(1, subSentence.length());subSentence += c;subSentence = add(subSentence);}return subSentence;}string toGoatLatin(string sentence) {int i = 0;string newString = "";string substring = "";int length = sentence.length();for (int k = 0; k < length; k++) {if (sentence[k] == ' ') {count += 1;newString += change(substring);newString += " ";substring = "";continue;}else if (k == (sentence.length() - 1)) {substring += sentence[k];count += 1;newString += change(substring);continue;}substring += sentence[k];}return newString;}
};int main()
{Solution solution;cout << solution.toGoatLatin("Each word consists of lowercase and uppercase letters only") << endl;return 0;
}