遍历呢?"/>
python基础——字典与列表相互嵌套的羁绊,怎么遍历呢?
本文介绍的是字典与列表相互嵌套时,该怎么遍历
1、遍历单个列表
# 生成一个列表
numbers = list(range(11))
# 遍历列表
for i in numbers:print("序号:", i)# 另一种写法
li = [i for i in range(10)]
# enumerate(),将一个遍历的对象组合成一个可索引的序列,同时列出数据和下标
for i in enumerate(li):print("序号:",i)
输出结果:
N1序号: 0
N1序号: 1
N1序号: 2
N1序号: 3
N1序号: 4
N1序号: 5
N1序号: 6
N1序号: 7
N1序号: 8
N1序号: 9
N1序号: 10
N2序号: (0, 0)
N2序号: (1, 1)
N2序号: (2, 2)
N2序号: (3, 3)
N2序号: (4, 4)
N2序号: (5, 5)
N2序号: (6, 6)
N2序号: (7, 7)
N2序号: (8, 8)
N2序号: (9, 9)
N2序号: (10, 10)
2、遍历字典键值对(items)、key值(keys)、values值(values)
dict_data = {"xiaotian": 101,"xiaoming": 102,"xiaohong": 103,"xiaolizi": 104
}
for key, values in dict_data.items():print(f"name: {key} , id: {values}")
for key in dict_data.keys():print(f"key:{key}")
for values in dict_data.values():print(f"value:{values}")
输出结果:
name: xiaotian , id: 101
name: xiaoming , id: 102
name: xiaohong , id: 103
name: xiaolizi , id: 104
key:xiaotian
key:xiaoming
key:xiaohong
key:xiaolizi
value:101
value:102
value:103
value:104
3、列表里嵌套字典
students = [{"id": 12, "name": "xiaotian", "grades": 88},{"id": 13, "name": "xiaoming", "grades": 99},{"id": 14, "name": "xiaohong", "grades": 77},
]
for student in students:id, name, grades = student["id"] , student["name"] , student["grades"]print(f"学生:{name},学号:{id},得分:{grades}")
输出结果:
学生:xiaotian,学号:12,得分:88
学生:xiaoming,学号:13,得分:99
学生:xiaohong,学号:14,得分:77
4、字典里嵌套列表
sports = {"xiaotian": ["篮球","足球"],"xiaoming": ["羽毛","足球","篮球"],"xiaohong": ["篮球","乒乓球"],
}
for student,sport in sports.items():print(f"学生:{student},喜欢的运动有:{sport}")
输出结果:
学生:xiaotian,喜欢的运动有:[‘篮球’, ‘足球’]
学生:xiaoming,喜欢的运动有:[‘羽毛’, ‘足球’, ‘篮球’]
学生:xiaohong,喜欢的运动有:[‘篮球’, ‘乒乓球’]
4、字典里嵌套字典
informations = {"xiaotian": {"id": 12, "grades": 88},"xiaoming": {"id": 13, "grades": 99},"xiaohong": {"id": 14, "grades": 77},
}
for name,info in informations.items():id , grades = info["id"] , info["grades"]print(f"学生:{name},学号为:{id},得分:{grades}")
输出结果:
学生:xiaotian,学号为:12,得分:88
学生:xiaoming,学号为:13,得分:99
学生:xiaohong,学号为:14,得分:77
5、混合嵌套
zidian = {"name": "护脸霜","innerCode": "dsjj1154","clusterSn": {"dataSourceType": "regular" , "bizSystem": "RDRSEW"},"description": "<p>1234567</p>","skuOptions": [{"id": 1, "name": "颜色", "naed": "尺码", "values": ["黑色", "白色"]}],"categoryId": "343b5dbff0654d779fd81f4d8259ce60","MinOrderType":{"keywords": "difhehdio","keyposswr": [{"userName": "18110522", "onedisty":[{"leg": "猪猪侠的腿", "hand": "猪猪侠的手"},{"leg": "煎饼侠的腿", "hand": "煎饼侠的手"}], "pwegdt": "猪猪侠的手表"}],"gbCode": "GBM852741","tableName": "test_table01",}}print(type(zidian))
# 输出结果:<class 'dict'>
print(zidian["categoryId"])
# 输出结果:343b5dbff0654d779fd81f4d8259ce60
print(zidian["name"])
# 输出结果:护脸霜
print(zidian["clusterSn"]["bizSystem"])
# 输出结果:RDRSEW
print(zidian["skuOptions"][0]["values"])
# 输出结果:['黑色', '白色']
print(zidian["MinOrderType"]["keyposswr"][0])
# 输出结果:{'userName': '18110522', 'onedisty': [{'zhu_leg': '猪猪侠的腿', 'zhu_hand': '猪猪侠的手'}], 'pwegdt': '猪猪侠的手表'}
混合嵌套的遍历:根据切片器,先定位到目标所在的
for name in zidian["MinOrderType"]["keyposswr"][0]["onedisty"]:leg, hand = name["leg"], name["hand"]print(leg, hand)
# 输出结果:
# 猪猪侠的腿 猪猪侠的手
# 煎饼侠的腿 煎饼侠的手
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python基础——字典与列表相互嵌套的羁绊,怎么遍历呢?
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