用函数交换a与b的值

函数交换a与b的值"/>

用函数交换a与b的值

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
void swap(int* pa, int* pb)//void 表示不返回值，如果要return什么，去掉void
{int z;z = *pa;*pa = *pb;*pb = z;
}
int main()
{int a = 10;int b = 20;printf("原来是：a=%d b=%d\n", a, b);swap(&a, &b);printf("现在是：a=%d b=%d", a, b);return 0;
}

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
void swap(int x, int y)
{int z = 0;;
z = x;
x = y;
y = z;
}
int main()
{int a = 10;int b = 20;printf("原来是：a=%d b=%d\n", a, b);swap(a, b);printf("现在是：a=%d b=%d", a, b);return 0;
}