mysql求和 子查询

编程入门 行业动态 更新时间:2024-10-07 10:23:16

<a href=https://www.elefans.com/category/jswz/34/1771279.html style=mysql求和 子查询"/>

mysql求和 子查询

这个问题留下了解释的空间.要UNION所有三个查询的结果行,然后选择具有最高“金额”的5行:

(SELECT event_id, count(*) AS amount

FROM pageview

GROUP BY event_id

ORDER BY pageviews DESC, rand()

LIMIT 1000)

UNION ALL

(SELECT event_id, count(*)

FROM upvote

GROUP BY event_id

ORDER BY upvotes DESC, rand()

LIMIT 1000)

UNION ALL

(SELECT event_id, count(*)

FROM attending

GROUP BY event_id

ORDER BY attendants DESC, rand()

LIMIT 1000)

ORDER BY 2 DESC

LIMIT 5;

The manual:

To apply ORDER BY or LIMIT to an individual SELECT, place the clause

inside the parentheses that enclose the SELECT.

UNION ALL,因此不会删除重复项.

如果要为每个event_id添加计数,则此查询应执行此操作:

SELECT event_id, sum(amount) AS total

FROM (

(SELECT event_id, count(*) AS amount

FROM pageview

GROUP BY event_id

ORDER BY pageviews DESC, rand()

LIMIT 1000)

UNION ALL

(SELECT event_id, count(*)

FROM upvote

GROUP BY event_id

ORDER BY upvotes DESC, rand()

LIMIT 1000)

UNION ALL

(SELECT event_id, count(*)

FROM attending

GROUP BY event_id

ORDER BY attendants DESC, rand()

LIMIT 1000)

) x

GROUP BY 1

ORDER BY sum(amount) DESC

LIMIT 5;

这里棘手的部分是并非所有三个基本查询都会出现每个event_id.因此,您必须注意JOIN不会完全丢失行,并且添加不会变为NULL.

使用UNION ALL,而不是UNION.您不想删除相同的行,而是想要添加它们.

x是AS x的简写 – 表别名.子查询需要具有名称.这里可以是任何其他名称.

SOL-feature FULL OUTER JOIN没有在MySQL中实现(我上次看过),所以你必须要使用UNION. FULL OUTER JOIN将加入所有三个基本查询而不会丢失行.

回答后续问题

SELECT event_id, sum(amount) AS total

FROM (

(SELECT event_id, count(*) / 100 AS amount

FROM pageview ... )

UNION ALL

(SELECT event_id, count(*) * 5

FROM upvote ... )

UNION ALL

(SELECT event_id, count(*) * 10

FROM attending ... )

) x

GROUP BY 1

ORDER BY sum(amount) DESC

LIMIT 5;

或者,如果您想以多种方式使用基本计数:

SELECT event_id

,sum(CASE source

WHEN 'p' THEN amount / 100

WHEN 'u' THEN amount * 5

WHEN 'a' THEN amount * 10

ELSE 0

END) AS total

FROM (

(SELECT event_id, 'p'::text AS source, count(*) AS amount

FROM pageview ... )

UNION ALL

(SELECT event_id, 'u'::text, count(*)

FROM upvote ... )

UNION ALL

(SELECT event_id, 'a'::text, count(*)

FROM attending ... )

) x

GROUP BY 1

ORDER BY 2 DESC

LIMIT 5;

更多推荐

mysql求和 子查询

本文发布于:2024-02-11 14:45:19,感谢您对本站的认可!
本文链接:https://www.elefans.com/category/jswz/34/1681533.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
本文标签:mysql

发布评论

评论列表 (有 0 条评论)
草根站长

>www.elefans.com

编程频道|电子爱好者 - 技术资讯及电子产品介绍!