什么是间隔重复算法来生成日间间隔?

本文介绍了什么是间隔重复算法来生成日间间隔?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在实施抽认卡游戏，并且我想实施间隔重复.我不需要SuperMemo中的复杂功能，而只需根据每张卡的得分来分配学习空间.

I am implementing a flashcard game and I want to implement spaced repetition. I don't need something complex like in SuperMemo, but simply space the learning based on the score for each card.

我目前正在寻找的是如何根据其得分计算直到再次显示卡片的天数.我发现ZDT使用以下屏幕截图中的列表(1、2、3、5等).有人知道如何动态生成此列表(以便我可以计算出12分以上的分数)吗?

What I am looking for at the moment is how to calculate the number of days until a card is shown again, based on its score. I found that ZDT uses the list in the screenshot below (1, 2, 3, 5, etc.). Does anybody know how to dynamically generate this list (so that I can calculate beyond a score of 12)?

或者也许有人会猜猜我可以使用什么数学函数来生成ZDT列表上的数字?它们成倍增加.

Or perhaps could someone guess what math function I could use to generate the numbers on the ZDT list? They increase exponentially.

推荐答案

它看起来非常类似于逻辑曲线.我将对其进行逻辑回归，看看会有什么结果.

It looks very similar to a logistic curve. I'll run a logistic regression on it and see what comes out.

以下是数据(使用WolframAlpha绘制)

Here is the data (plotted using WolframAlpha)

这是我得到的等式:

f(x) = 115/(1+2192*EXP(-0.79*x))

这是带有曲线的图:

不幸的是，对于较小的数字，曲线不是很准确.

Unfortunately the curve isn't very accurate for small numbers.