本文介绍了重复值n次的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个值的集合
[1, 4, 23, 90],这些值应存储到重复 3 次且不重复的数组中使用 Linq
and these values should be stored into a array repeated 3 times without using Linq
[1, 1, 1, 4, 4, 4, 23, 23, 23, 90, 90, 90]到目前为止我已经尝试过的
what I've tried so far
int[] collection = { 1, 4, 23, 90 }; int multiplier = 3; int[] result = new int[collection.Length * multiplier]; for (int i = 0; i < collection.Length; i++) for (int j = 0; j < multiplier; j++) result[i + j] = collection[i];但不知何故,只有$ 6 个字段数组已填充
but somehow only the first 6 fields of the array are filled
推荐答案如果您不是正在寻找 Linq 解决方案,
If you are not looking for a Linq solution,
插入重复值linq
然后只需计算要放入结果中的项目: i 次结果的项目对应于 i /乘数 集合$ c $ s一个
then just compute which item to put into result: i-th result's item corresponds to i / multiplier collections one
int[] collection = new int[] { 0, 2, 25, 30 }; int multiplier = 3; int[] result = new int[collection.Length * multiplier]; for (int i = 0; i < result.Length; i++) result[i] = collection[i / multiplier];更多推荐
重复值n次
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