SuDoKu挑战

本文介绍了SuDoKu挑战的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我是Visual Basic的新手，并开始使用我给出的第4版副本。我很迷恋。我喜欢编写代码，并期待在不同的代码项目中创建我自己的旋转，就像你们其他人一样。 我已经整理了一个小程序，完全击败了死亡一词SuDoKu和生成要显示的板（阵列）有困难。 到目前为止我已经这样做了： [Dim MyNum（9,9）作为整数] [x = 1到9] [y = 1 ro 9] [newZ：] [随机] [z = Int（（9 * RND）+ 1 ）] [如果y = 1则转到getnewnum] [w =（y - 1）到1步-1] [如果MyNum（x，y）= MyNum（x，w）然后转到newZ] [下一个w] [如果x = 1然后转到getnewnum] [对于v =（x - 1）到1步-1] [如果MyNum（x，y）= MyNum（v， y）然后转到newZ] [下一个v] [getnewnum] [下一个，x] 我做过家庭作业网页作者提出的建议。我看到很多帖子都是为有经验的程序员编写的，但对我来说都没有。有没有人知道如何帮助我甚至想尝试？ 我将不胜感激。

I am totally new to Visual Basic and started out with a copy of version 4 that I was given. I am hooked. I enjoy writing code and am looking forward to creating my own spins on different code projects just like the rest of you. I have put together a small program for the totally beat-to-death term SuDoKu and am having trouble with generating the boards (arrays) to display. I have did this thus far: [Dim MyNum(9,9) As Integer] [ for x = 1 to 9 ] [ for y = 1 ro 9 ] [newZ:] [Randomize] [z = Int( ( 9 * RND) + 1)] [if y = 1 then goto getnewnum] [ for w = ( y - 1) to 1 Step -1] [ if MyNum(x , y) = MyNum(x , w) then goto newZ] [ next w] [if x = 1 then goto getnewnum] [ for v = (x - 1) to 1 Step -1] [ if MyNum(x , y) = MyNum(v , y) then goto newZ] [ next v] [getnewnum] [next y, x] I have done the "homework" suggested by the web page authors. There are many posts that I see that are written for you more experienced programmers, but none for me. Does anyone have a clue how to assist me or even want to try? I would appreciate some assistance.

推荐答案

这可能是帮助： 随机填充阵列

我有alreaady看过这个帖子，这似乎让人感到困惑。我不希望将数组中的任何数字转换为1的1。另外，在我发布原始帖子之前尝试使用我的3 x 3数组和垂直数组（列）中的重复项代码。 似乎没人走过第一排。只有SuDoKu书籍制作者才有能力做到这一点吗？我猜想VB4足够强大，可以完成这项任务，但我完全愿意承认我错了，因为我是新手。 困惑！ !!!!!!!!!! I have alreaady viewed that post and it seemed way to confusing. I did not wish to convert any of the numbers in the arrays to just "1''s" and "2''s". Additionally, trying the code before I made my original post left me with duplicates in my 3 x 3 arrays and in my vertical arrays (columns). No one seems to go past the first row. Do only SuDoKu book makers have the ability to do this? I would guess that VB4 is powerful enough to handle this task, but fully willing to admit that I could be wrong because I am new. Confused!!!!!!!!!!!

我有alreaady看过这篇帖子，这似乎让人感到困惑。我不希望将数组中的任何数字转换为1的1。另外，在我发布原始帖子之前尝试使用我的3 x 3数组和垂直数组（列）中的重复项代码。 似乎没人走过第一排。只有SuDoKu书籍制作者才有能力做到这一点吗？我猜想VB4足够强大，可以完成这项任务，但我完全愿意承认我错了，因为我是新手。 困惑！ !!!!!!!!!! I have alreaady viewed that post and it seemed way to confusing. I did not wish to convert any of the numbers in the arrays to just "1''s" and "2''s". Additionally, trying the code before I made my original post left me with duplicates in my 3 x 3 arrays and in my vertical arrays (columns). No one seems to go past the first row. Do only SuDoKu book makers have the ability to do this? I would guess that VB4 is powerful enough to handle this task, but fully willing to admit that I could be wrong because I am new. Confused!!!!!!!!!!!

查看las选项，在这种情况下，对于数独，只考虑3x3方格，开始生成第1，第4和第7行： 123456789 234567891 345678912 然后是第2，第5和第8，最后是第3，第6和第9，将是这样的： 123456789 456789123 879123456 234567891 567891234 891235467 345678912 678912345 912345678 然后只是随机更改列和行，但请确保您只更改列 1与2或3， 4 5或6， 7,8或9和行相同.. 你也可以改变3列和3行的集合 这是一个随机的次数，你会有一个不错的数独板

Check out the las option, in this case, for the sudoku, only consider the 3x3 squares, start generating the 1st, 4th and 7th row: 123456789 234567891 345678912 then the 2nd, 5th and 8th, and finaly the 3rd, 6th and 9th, will be something like: 123456789 456789123 879123456 234567891 567891234 891235467 345678912 678912345 912345678 Then just randomly change columns and rows, but be sure that you''ll only change column 1 with 2 or 3, 4 with 5 or 6, 7 with 8 or 9 and the same for rows.. you can also change sets of 3 columns and sets of 3 rows do this a random number of times and you''ll have a nice sudoku board