本文介绍了拆分数组到红宝石等份的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要一种方法来在一堆数组的大小相等的另一个数组中拆分阵列。任何人有这样做的任何方法?
例如
A = [0,1,2,3,4,5,6,7]a.method_i_need(3)a.inspect = GT; [[0,1,2],[3,4,5],[6,7]]解决方案
您正在寻找的Enumerable#each_slice
A = [0,1,2,3,4,5,6,7]a.each_slice(3)#=> #&所述;枚举:[0,1,2,3,4,5,6,7]:each_slice(3)>a.each_slice(3).to_a#=> [0,1,2],[3,4,5],[6,7]I need a way to split an array in to a bunch of arrays within another array of equal size. Anyone have any method of doing this?
For instance
a = [0, 1, 2, 3, 4, 5, 6, 7] a.method_i_need(3) a.inspect => [[0,1,2], [3,4,5], [6,7]]解决方案
You're looking for Enumerable#each_slice
a = [0, 1, 2, 3, 4, 5, 6, 7] a.each_slice(3) # => #<Enumerator: [0, 1, 2, 3, 4, 5, 6, 7]:each_slice(3)> a.each_slice(3).to_a # => [[0, 1, 2], [3, 4, 5], [6, 7]]
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拆分数组到红宝石等份
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