基于值拆分数组

本文介绍了基于值拆分数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

自从我不得不处理一些javascript代码以来，已经很长时间了。我生气了。

It's been a long time since I had to work on some javascript code and I'm a lot rusty.

我需要拆分这样的数组：

I need to split an array like this:

Object ( [0] => 2013-04-12 [1] => text [2] => text [3] => text [4] => text [5] => 2013-04-11 [6] => text [7] => text [8] => text [9] => text [10] => text [11] => text [12] => 2013-04-10 [13] => text [14] => text [15] => text [16] => text [17] => 2013-04-09 [18] => text [19] => text [20] => text )

进入json对象或数组，其中索引0始终是日期：

into json objects or arrays where index 0 is always the date:

Object0 ( [0] => 2013-04-12 [1] => text [2] => text [3] => text [4] => text ) Object1 ( [0] => 2013-04-11 [1] => text [2] => text [3] => text [4] => text [5] => text [6] => text ) Object2 ( [0] => 2013-04-10 [1] => text [2] => text [3] => text [4] => text ) Object3 ( [0] => 2013-04-09 [1] => text [2] => text [3] => text )

所以你可以看到，我只能使用该值来计算每个新数组，这些数组可以有不同的大小。

So as you can see, I can only use the value to figure out each new array, which can be of different sizes.

感谢您的帮助。

更新 抱歉，我没有在最初的问题中发布我的代码，因为我写的东西太废了（我感到非常惭愧）。 这里我使用的代码归功于Bangerang的解决方案。 感谢大家的帮助和贡献。

UPDATE Sorry I didn't publish my code in the initial question because what I had written was way too crap (and I was very ashamed). Here the code I used in the end thanks to the solution from Bangerang. Thanks everyone for your help and contributions.

var events = []; var result = []; var j = 0; for (var i = 0; i < tableData.length; i++){ if (/^(\d{4})-(\d{2})-(\d{2})$/.test(tableData[i])){ //Returning true if it's just numbers j = j + 1; events[j] = []; events[j].push(tableData[i]); result.push(events[j]); } else { events[j].push(tableData[i]); } } // Then I write the json message which will be eval to use with FullCalendar. var json_events = '['; for (var i = 1; i <= events.length; i++){ if (typeof events[i] !== 'undefined' && events[i].length > 0) { for (var j = 0; j < events[i].length; j++){ if(/@/.test(events[i][j])){ json_events += '{"start":"' + events[i][0] + '",'; json_events += '"textColor":"black",'; var tmp = events[i][j].split("@"); json_events += '"backgroundColor":"' + tmp[0] + '",'; var text_pattern = new RegExp(/<b>([a-z_]+)<\/b>(.+)/); var title_desc = text_pattern.exec(tmp[1]); json_events += '"title":"' + title_desc[1] + '",'; json_events += '"description":"' + title_desc[0] + '"'; json_events += '},'; } } } } json_events += ']'; json_events = json_events.replace("},]","}]");

推荐答案

假设日期是唯一只有数字的日期你可以试试这个：

Assuming that the date's is the only ones with just numbers in it you can try this:

var object = []; var result = []; for (var i = 0; i < objects.length; i++){ if (/^\d+$/.test(objects[i])){ //Returning true if it's just numbers object = [] object.push(objects[i]); result.push(object); }else { object.push(objects[i]); } }