相乘在PHP两个数组

本文介绍了相乘在PHP两个数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我乘两个数组是一个挑战。这就是我打算做的。

数组1（[0] =＆GT; 2 [1] =＆GT; 2）数组2（[0] =＆GT; 8000.00 [1] =＆GT; 1234.00）

每次我乘这一点，将其分解为4个，并返回一个结果，因为这

阵列（[0] =＆GT; 16000 [1] =＆GT; 16000 [2] =＆GT; 2468 [3] =＆GT; 2468）

然而，当我通过单一它得到正确的单个数据。这里是我的code，我将AP preciate任何帮助，我可以得到的。谢谢

$ =总阵列（）;的foreach（$ office_price为$价格）{    的foreach（$ office_quantity为$数量）{        $总[] = $价格* $数量;    }}

解决方案

您遍历两个数组，所以你得到的每一个值的两倍。

如你所知，一个阵列建成使用键和值。

使用您的foreach到那个程度：

$ =总阵列（）;的foreach（$ office_price为$关键=＆GT; $价格）{    $总[] = $价格* $ office_quantity [$关键];}

您只需要循环一个阵列，并且通过使用具有相同密钥对第二阵列的价值，你得到正确的结果。

I have a challenge multiplying two arrays. this is what i intend doing

Array1 ( [0] => 2 [1] => 2 ) Array2 ( [0] => 8000.00 [1] => 1234.00 )

Every time i multiply this it breaks it down into 4 and returns a result as this

Array ( [0] => 16000 [1] => 16000 [2] => 2468 [3] => 2468 )

However when i pass single a single data it gets it right. Here is my code, i'll appreciate any help i can get. Thanks

$total = array(); foreach($office_price as $price){ foreach($office_quantity as $quantity){ $total[] = $price * $quantity; } }

解决方案

You loop through both arrays, so you get every value twice.

As you know, an array is built up using keys and values.

Use your foreach to that extent:

$total = array(); foreach ($office_price as $key=>$price) { $total[] = $price * $office_quantity[$key]; }

You only need to loop one array, and by using the value from the second array with the same key, you get the proper result.