javascript旋转数组元素

本文介绍了javascript旋转数组元素的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

大家好，我有这个任务:我有一个数组[4,7,3,6,9]，我必须制作一个像这样的数组:

Hello, everybody, I have this task: I have an array [4,7,3,6,9] and I have to make an array like this:

[4,7,3,6,9] [9,4,7,3,6] [6,9,4,7,3] [3,6,9,4,7] [7,3,6,9,4]

即使我向数组添加新项目，我也必须编写一个数组旋转的程序.我是JS的新手，大约1周左右，这是我目前的尝试:

I have to make a program where array is rotating even if I add a new item to an array it should change accordingly. I am total newbie at JS, 1 week or so, here is my current try:

var numbers = [4, 7, 3, 6, 9]; console.log(numbers); numbers[0] = 9; numbers[1] = 4; numbers[2] = 7; numbers[3] = 3; numbers[4] = 6; console.log(numbers); numbers[0] = 6; numbers[1] = 9; numbers[2] = 4; numbers[3] = 7; numbers[4] = 3; console.log(numbers); numbers[0] = 3; numbers[1] = 6; numbers[2] = 9; numbers[3] = 4; numbers[4] = 7; console.log(numbers); numbers[0] = 7; numbers[1] = 3; numbers[2] = 6; numbers[3] = 9; numbers[4] = 4; console.log(numbers);

在我看来，我也有.push，.splice等.我不知道为什么，但是我真的觉得javascript不适合我的大脑，哈哈:D

Also in my mind I have .push, .splice, etc. I dont know why but i really feel that javascript is not for my brain, haha :D

推荐答案

您可以弹出该值并将其取消移位.

You could pop the value and unshift it.

var array = [4, 7, 3, 6, 9], i = array.length; while (i--) { console.log(array.join(' ')); array.unshift(array.pop()); } console.log(array.join(' '));