json 对象的完整路径

本文介绍了json 对象的完整路径的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试展平一个对象，其中键将是叶节点的完整路径.我可以递归地识别哪些是叶节点，但在尝试构建整个路径时卡住了.

样本输入:

{一:1，二: {三:3},四:{五:5，六: {七:7},八:8},九:9}

输出:

{一:1，'二三':3，'四.五':5，'四.六.七': 7,'四.八':8，九:9}

解决方案

您可以使用递归方法并收集对象的键.这个提议也寻找数组.

function getFlatObject(object) {函数迭代器(o，p){if (o && typeof o === 'object') {Object.keys(o).forEach(function (k) {iter(o[k], p.concat(k));});返回;}路径[p.join('.')] = o;}变量路径 = {};迭代器(对象，[])；返回路径；}var obj = {一:1，二:{三:3}，四:{五:5，六:{七:7}，八:8}，九:9}，路径 = getFlatObject(obj);console.log(path);

I'm trying to flatten an object where the keys will be the full path to the leaf node. I can recursively identify which are the leaf nodes but stuck trying to construct the whole path.

Sample Input:

{ one: 1, two: { three: 3 }, four: { five: 5, six: { seven: 7 }, eight: 8 }, nine: 9 }

Output:

{ one: 1, 'two.three': 3, 'four.five': 5, 'four.six.seven': 7, 'four.eight': 8, nine: 9 }

解决方案

You could use a recursive approch and collect the keys of the object. This proposal looks for arrays as well.

function getFlatObject(object) { function iter(o, p) { if (o && typeof o === 'object') { Object.keys(o).forEach(function (k) { iter(o[k], p.concat(k)); }); return; } path[p.join('.')] = o; } var path = {}; iter(object, []); return path; } var obj = { one: 1, two: { three: 3 }, four: { five: 5, six: { seven: 7 }, eight: 8 }, nine: 9 }, path = getFlatObject(obj); console.log(path);