创建数组的副本并处理原始数组

本文介绍了创建数组的副本并处理原始数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我将从对我英语不好的人道歉开始。我会尽量保持清楚。 ：）

I will start with an apology about my poor English. I will try to be as clear as I can. :)

我有一个3维数组（只是2维数组的数组）。我的目标是采用二维数组之一，并将其​​逆时针旋转90°。看起来像这样：

I have a 3-dimensional array (just an array of 2-dimensional arrays). My goal is to take one of the 2-dimensional arrays, and rotate it 90° counterclockwise. It look like this:

[1|2|3] [4|5|6] [7|8|9]

我尝试使它像这样旋转：

I try to make it "rotate" like this:

[3|6|9] [2|5|8] [1|4|7]

我想更改原始数组，所以我想需要创建一个副本所以我将为您提供参考。所以，这就是我所做的：

I want to change the original array, so I figured that I need to create a copy of it so i will have a reference to work with. So, here is what I have done:

var temp = []; var cube = [ [ ['A', 'A', 'A'], ['A', 'A', 'A'], ['A', 'A', 'A'] ], [ ['B', 'B', 'B'], ['B', 'B', 'B'], ['B', 'B', 'B'] ], [ ['C', 'C', 'C'], ['C', 'C', 'C'], ['C', 'C', 'C'] ], [ ['D', 'D', 'D'], ['D', 'D', 'D'], ['D', 'D', 'D'] ], [ ['1', '2', '3'], ['4', '5', '6'], ['7', '8', '9'] ], [ ['F', 'F', 'F'], ['F', 'F', 'F'], ['F', 'F', 'F'] ] ]; function CCW() { temp = temp.concat(cube[4]); for(var i = 0; i < 3; i++) for(var j = 0; j < 3; j++) cube[4][i][j] = temp[j][2-i]; } CCW();

原始数组的副本应位于 temp 。

The copy of the original array should be in temp.

现在，问题出在这一行： cube [4] [i] [j] = temp [j] [2 -i]; 。除了更改 cube 中的数组的值外，它还更改 temp 的值。我试图将 temp = temp.concat（cube [4]）; 更改为 temp = cube [4] .slice（0）; ，但没有任何区别。

Now, the problem is in this line: cube[4][i][j] = temp[j][2-i];. Instead of changing only the values of the array in cube, it changes also the values of temp. I tried to change temp = temp.concat(cube[4]); to temp = cube[4].slice(0); but it did not make any diffrence.

我该如何解决？谢谢你们。 ：）

How can I fix that? Thank you all. :)

推荐答案

直接分配数组时，它是javascript中的引用分配。这意味着任何更改都将反映在两者中。要复制数组，您需要调用array.slice（）。

when you assign an array directly, it is a reference assignment in javascript. This means that any changes will be reflected in both. To copy an array, you will need to call array.slice().

注意：这仍然是多维数组上的赋值，因此您需要写一些递归的东西来复制一个具有多个维度的数组（在任何元素上，例如[1、2，['some'，'inner'，'array']，3]）

note: this will still be an assignment on a multi-dimensional array, so you will need to write something recursive to copy an array that has more than one dimension (at any element, e.g. [1, 2, ['some', 'inner', 'array'], 3])

可以清除这种东西吗？

编辑：这是一个deepCopyArray函数，需要将其扩展为任意对象，不过...

edit: here's a deepCopyArray function, this needs to be exanded for arbitrary objects, though...

function deepCopyArray(arr) { var newArr = []; for (var i = 0; i < arr.length; i++) { var a = arr[i], ele; if (a instanceof Array) //current element is an array... ele = deepCopyArray(a); else ele = a; newArr.push(ele); } return newArr; }