本文介绍了添加/编辑Javascript程序来计算数组元素的最小值,最大值,总计和平均值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
myArray = new Array(1,4,3,2,7,6,5,9,8,10,0) document.write(< pre>>) document.write(myArray.toString()\ t:\ t \ t) document.write(myArray.toString()+) document.write(myArray.join(' - ')\:\ t \ t) document.write(myArray.join( - )+) document.write(myArray.reverse()\ t:\ t \ t) document.write(myArray.reverse()+) document.write(myArray。 sort()\t\t:\ t\t) document.write(myArray.sort()+) var min = Math.min.apply(null,myArray); var max = Math.max.apply(null,myArray);
总计
var sum = myArray.reduce(function(a,b){ return a + b; });资料来源: developer.mozilla/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce
平均值只需将总和除以数组元素的数量:
var average = myArray.reduce(function(a,b){ return a + b; })/ myArray.length;myArray = new Array(1, 4, 3, 2, 7, 6, 5, 9, 8, 10, 0) document.write("<pre>") document.write("myArray.toString()\t:\t\t") document.write(myArray.toString()+"") document.write("myArray.join('-')\t:\t\t") document.write(myArray.join ("-")+"") document.write("myArray.reverse()\t:\t\t") document.write(myArray.reverse()+"") document.write("myArray.sort()\t\t:\t\t") document.write(myArray.sort()+"")
解决方案
Minimum and maximum
var min = Math.min.apply(null, myArray); var max = Math.max.apply(null, myArray);Total
var sum = myArray.reduce(function(a, b) { return a + b; });Source: developer.mozilla/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce
AverageJust divide sum by the number of array elements:
var average = myArray.reduce(function(a, b) { return a + b; })/myArray.length;
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添加/编辑Javascript程序来计算数组元素的最小值,最大值,总计和平均值
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