我有一些包含 50 多个这样的名字的数组.
["dan", "ryan", "bob", "steven", "corbin"][鲍勃"、丹"、史蒂文"、科尔宾"]我有另一个具有正确顺序的数组.请注意，上面的第二个数组不包括所有名称，但我仍然希望它遵循以下顺序:
["ryan", "corbin", "dan", "steven", "bob"]它没有逻辑顺序，它们只是按照这个顺序.对我来说有意义的是将每个数组与正确排序的数组进行比较.我想我看到有些人用 PHP 做这件事，但我找不到 JavaScript 解决方案.有谁知道如何做到这一点?我已经尝试了几个小时，但被难住了.
解决方案使用 indexOf() 获取每个元素在引用数组中的位置，并在您的比较函数中使用.>
var reference_array = ["ryan", "corbin", "dan", "steven", "bob"];var array = ["bob", "dan", "steven", "corbin"];数组排序(函数(a，b){返回 reference_array.indexOf(a) - reference_array.indexOf(b);});控制台日志(数组)；//["corbin", "dan", "steven", "bob"]每次搜索参考数组对于大数组来说效率很低.如果这是一个问题，您可以将其转换为将名称映射到位置的对象:
var reference_array = ["ryan", "corbin", "dan", "steven", "bob"];参考对象 = {};for (var i = 0; iI have a few arrays of 50+ names like this.
["dan", "ryan", "bob", "steven", "corbin"] ["bob", "dan", "steven", "corbin"]I have another array that has the correct order. Note that the second array above does not include all of the names, but I still want it to follow the order of the following:
["ryan", "corbin", "dan", "steven", "bob"]There is no logical order to it, they are just in this order. What makes sense to me is to compare each array against the correctly ordered one. I think I saw some people doing this with PHP, but I was not able to find a JavaScript solution. Does anyone have any idea how to do this? I've been trying for a few hours and I'm stumped.
解决方案Use indexOf() to get the position of each element in the reference array, and use that in your comparison function.
var reference_array = ["ryan", "corbin", "dan", "steven", "bob"]; var array = ["bob", "dan", "steven", "corbin"]; array.sort(function(a, b) { return reference_array.indexOf(a) - reference_array.indexOf(b); }); console.log(array); // ["corbin", "dan", "steven", "bob"]
Searching the reference array every time will be inefficient for large arrays. If this is a problem, you can convert it into an object that maps names to positions:
var reference_array = ["ryan", "corbin", "dan", "steven", "bob"]; reference_object = {}; for (var i = 0; i < reference_array.length; i++) { reference_object[reference_array[i]] = i; } var array = ["bob", "dan", "steven", "corbin"]; array.sort(function(a, b) { return reference_object[a] - reference_object[b]; }); console.log(array);
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